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chenwenhang
AlgorithmPractice
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MultiplyStrings.java
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45 lines (41 loc) · 1.56 KB
master
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MultiplyStrings.java
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package other;
/**
* @Author: Wenhang Chen
* @Description:给定两个以字符串形式表示的非负整数 num1 和 num2,返回 num1 和 num2 的乘积,它们的乘积也表示为字符串形式。
* 示例 1:
* <p>
* 输入: num1 = "2", num2 = "3"
* 输出: "6"
* <p>
* 示例 2:
* <p>
* 输入: num1 = "123", num2 = "456"
* 输出: "56088"
* @Date: Created in 12:32 12/14/2019
* @Modified by:
*/
public class MultiplyStrings {
public String multiply(String num1, String num2) {
if (num1.equals("0") || num2.equals("0")) return "0";
// 乘数 num1 位数为 M,被乘数 num2 位数为 N, num1 x num2 结果 res 最大总位数为 M+N
// num1[i] x num2[j] 的结果为 tmp(位数为两位,"0x","xy"的形式),其第一位位于 res[i+j],第二位位于 res[i+j+1]。
// 最大总位数为M+N
int[] res = new int[num1.length() + num2.length()];
for (int i = num1.length() - 1; i >= 0; i--) {
// 从地位向高位(从后往前)
int n1 = num1.charAt(i) - '0';
for (int j = num2.length() - 1; j >= 0; j--) {
int n2 = num2.charAt(j) - '0';
int sum = (res[i + j + 1] + n1 * n2);
res[i + j + 1] = sum % 10; // 个位
res[i + j] += sum / 10; // 十位
}
}
StringBuilder result = new StringBuilder();
for (int i = 0; i < res.length; i++) {
if (i == 0 && res[i] == 0) continue;
result.append(res[i]);
}
return result.toString();
}
}
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