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chenwenhang
AlgorithmPractice
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array_and_matrix
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JumpGame.java
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master
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AlgorithmPractice
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array_and_matrix
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JumpGame.java
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package array_and_matrix;
/**
* @Author: Wenhang Chen
* @Description:给定一个非负整数数组,你最初位于数组的第一个位置。 数组中的每个元素代表你在该位置可以跳跃的最大长度。
* <p>
* 判断你是否能够到达最后一个位置。
* <p>
* 示例 1:
* <p>
* 输入: [2,3,1,1,4]
* 输出: true
* 解释: 我们可以先跳 1 步,从位置 0 到达 位置 1, 然后再从位置 1 跳 3 步到达最后一个位置。
* 示例 2:
* <p>
* 输入: [3,2,1,0,4]
* 输出: false
* 解释: 无论怎样,你总会到达索引为 3 的位置。但该位置的最大跳跃长度是 0 , 所以你永远不可能到达最后一个位置。
* @Date: Created in 9:45 1/14/2020
* @Modified by:
*/
public class JumpGame {
public boolean canJump(int[] nums) {
if (nums == null || nums.length < 1) return true;
int end = nums.length - 1;
// 起初将目的位置和当前位置都设置为数组的最后一个位置
// 从后往前遍历,用当前位置的值减去 当前位置与目的位置的距离
// 如果大于等于0代表当前位置能跳到目的位置,则将当前位置设置为目的位置
// 否则继续往前遍历,寻找符合要求的位置
// 直到目的位置为起点跳出
for (int i = nums.length - 1; i >= 0; i--) {
nums[i] = nums[i] - (end - i);
if (nums[i] >= 0) {
end = i;
}
}
return end == 0;
}
}
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